l=(b-c)/2

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Solution for l=(b-c)/2 equation: 


x in (-oo:+oo)

l = (b-c)/2 // - (b-c)/2

l-((b-c)/2) = 0

(-1*(b-c))/2+l = 0

(-1*(b-c))/2+(2*l)/2 = 0

2*l-1*(b-c) = 0

c-b+2*l = 0

(c-b+2*l)/2 = 0

(c-b+2*l)/2 = 0 // * 2

c-b+2*l = 0

x belongs to the empty set

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