lg(x+1)+lg(x-1)=1

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Solution for lg(x+1)+lg(x-1)=1 equation:


Simplifying
lg(x + 1) + lg(x + -1) = 1

Reorder the terms:
gl(1 + x) + lg(x + -1) = 1
(1 * gl + x * gl) + lg(x + -1) = 1
(1gl + glx) + lg(x + -1) = 1

Reorder the terms:
1gl + glx + gl(-1 + x) = 1
1gl + glx + (-1 * gl + x * gl) = 1
1gl + glx + (-1gl + glx) = 1

Reorder the terms:
1gl + -1gl + glx + glx = 1

Combine like terms: 1gl + -1gl = 0
0 + glx + glx = 1
glx + glx = 1

Combine like terms: glx + glx = 2glx
2glx = 1

Solving
2glx = 1

Solving for variable 'g'.

Move all terms containing g to the left, all other terms to the right.

Divide each side by '2lx'.
g = 0.5l-1x-1

Simplifying
g = 0.5l-1x-1

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