ln(-1/100*120)=ln(x)

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Solution for ln(-1/100*120)=ln(x) equation: 


D( x )

x <= 0

x <= 0

x in (0:+oo)

ln(120*(-1/100)) = ln(x) // - ln(x)

ln(120*(-1/100))-ln(x) = 0

ln(-6/5)-ln(x) = 0 // - ln(-6/5)

-ln(x) = -ln(-6/5)

-ln(x) = -ln(-6/5) // * -1

x = -6/5

x in { -6/5} 

x belongs to the empty set

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