ln(0.5)/ln(X)=20

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Solution for ln(0.5)/ln(X)=20 equation:


D( X )

ln(X) = 0

X <= 0

ln(X) = 0

ln(X) = 0

ln(X) = ln(e^0)

X = e^0

X = 1

X <= 0

X in (0:1) U (1:+oo)

ln(0.5)/ln(X) = 20 // - 20

ln(0.5)/ln(X)-20 = 0

t_2 = ln(X)

ln(0.5)/t_2-20 = 0

ln(0.5)*t_2^-1 = 20 // : ln(0.5)

t_2^-1 = 20/ln(0.5)

-1 < 0

1/(t_2^1) = 20/ln(0.5) // * t_2^1

1 = (20/ln(0.5))*t_2^1 // : 20/ln(0.5)

1/(20/ln(0.5)) = t_2^1

t_2 = 1/(20/ln(0.5))

ln(X) = 1/(20/ln(0.5))

ln(X) = ln(e^(1/(20/ln(0.5))))

X = e^(1/(20/ln(0.5)))

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