ln(1-x)=1/4

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Solution for ln(1-x)=1/4 equation: 


D( x )

1-x <= 0

1-x <= 0

1-x <= 0

1-x <= 0

-x <= -1 // * -1

x >= 1

x in (-oo:1)

ln(1-x) = 1/4 // - 1/4

ln(1-x)-(1/4) = 0

ln(1-x)-1/4 = 0

ln(1-x)-1/4 = 0 // + 1/4

ln(1-x) = 1/4

ln(1-x) = ln(e^(1/4))

1-x = e^(1/4)

1-x-e^(1/4) = 0 // - 1-e^(1/4)

-x = -(1-e^(1/4)) // * -1

x = 1-e^(1/4)

x = 1-e^(1/4)

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