ln(1-x)=ln(1-x)

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Solution for ln(1-x)=ln(1-x) equation:


Simplifying
ln(1 + -1x) = ln(1 + -1x)
(1 * ln + -1x * ln) = ln(1 + -1x)
(1ln + -1lnx) = ln(1 + -1x)
1ln + -1lnx = (1 * ln + -1x * ln)
1ln + -1lnx = (1ln + -1lnx)

Add '-1ln' to each side of the equation.
1ln + -1ln + -1lnx = 1ln + -1ln + -1lnx

Combine like terms: 1ln + -1ln = 0
0 + -1lnx = 1ln + -1ln + -1lnx
-1lnx = 1ln + -1ln + -1lnx

Combine like terms: 1ln + -1ln = 0
-1lnx = 0 + -1lnx
-1lnx = -1lnx

Add 'lnx' to each side of the equation.
-1lnx + lnx = -1lnx + lnx

Combine like terms: -1lnx + lnx = 0
0 = -1lnx + lnx

Combine like terms: -1lnx + lnx = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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