ln(2+sinx)=0

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Solution for ln(2+sinx)=0 equation: 


Simplifying
ln(2 + sinx) = 0
(2 * ln + insx * ln) = 0

Reorder the terms:
(iln2sx + 2ln) = 0
(iln2sx + 2ln) = 0

Solving
iln2sx + 2ln = 0

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '-2ln' to each side of the equation.
iln2sx + 2ln + -2ln = 0 + -2ln

Combine like terms: 2ln + -2ln = 0
iln2sx + 0 = 0 + -2ln
iln2sx = 0 + -2ln
Remove the zero:
iln2sx = -2ln

Divide each side by 'ln2sx'.
i = -2n-1s-1x-1

Simplifying
i = -2n-1s-1x-1

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