ln(2.5/x)=0.002

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Solution for ln(2.5/x)=0.002 equation: 


D( x )

x = 0

2.5/x <= 0

x = 0

x = 0

2.5/x <= 0

2.5/x <= 0

2.5*x^-1 <= 0

2.5*x^-1 <= 0 // : 2.5

x^-1 <= 0/2.5

x^-1 <= 0

1/(x^1) <= 0

x <> 0

1/(x^1) <= 0 // * x^2

(x^2)/(x^1) <= 0

x^1 <= 0

x <= 0

x in (-oo:0)

x in (0:+oo)

ln(2.5/x) = 0.002 // - 0.002

ln(2.5/x)-0.002 = 0

ln(2.5/x)-0.002 = 0 // + 0.002

ln(2.5/x) = 0.002

ln(2.5/x) = ln(e^0.002)

2.5/x = e^0.002

2.5/x-e^0.002 = 0

2.5*x^-1 = e^0.002 // : 2.5

x^-1 = 0.4*e^0.002

-1 < 0

1/(x^1) = 0.4*e^0.002 // * x^1

1 = 0.4*e^0.002*x^1 // : 0.4*e^0.002

2.5*e^-0.002 = x^1

x = 2.5*e^-0.002

x = 2.5*e^-0.002

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