ln(2x+1)-ln(3x+-1)=2

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Solution for ln(2x+1)-ln(3x+-1)=2 equation:


Simplifying
ln(2x + 1) + -1ln(3x + -1) = 2

Reorder the terms:
ln(1 + 2x) + -1ln(3x + -1) = 2
(1 * ln + 2x * ln) + -1ln(3x + -1) = 2
(1ln + 2lnx) + -1ln(3x + -1) = 2

Reorder the terms:
1ln + 2lnx + -1ln(-1 + 3x) = 2
1ln + 2lnx + (-1 * -1ln + 3x * -1ln) = 2
1ln + 2lnx + (1ln + -3lnx) = 2

Reorder the terms:
1ln + 1ln + 2lnx + -3lnx = 2

Combine like terms: 1ln + 1ln = 2ln
2ln + 2lnx + -3lnx = 2

Combine like terms: 2lnx + -3lnx = -1lnx
2ln + -1lnx = 2

Solving
2ln + -1lnx = 2

Solving for variable 'l'.

Move all terms containing l to the left, all other terms to the right.

Reorder the terms:
-2 + 2ln + -1lnx = 2 + -2

Combine like terms: 2 + -2 = 0
-2 + 2ln + -1lnx = 0

The solution to this equation could not be determined.

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