ln(2x+3)+ln(x+1)=7

Solution for ln(2x+3)+ln(x+1)=7 equation:

Simplifying
ln(2x + 3) + ln(x + 1) = 7

Reorder the terms:
ln(3 + 2x) + ln(x + 1) = 7
(3 * ln + 2x * ln) + ln(x + 1) = 7
(3ln + 2lnx) + ln(x + 1) = 7

Reorder the terms:
3ln + 2lnx + ln(1 + x) = 7
3ln + 2lnx + (1 * ln + x * ln) = 7
3ln + 2lnx + (1ln + lnx) = 7

Reorder the terms:
3ln + 1ln + 2lnx + lnx = 7

Combine like terms: 3ln + 1ln = 4ln
4ln + 2lnx + lnx = 7

Combine like terms: 2lnx + lnx = 3lnx
4ln + 3lnx = 7

Solving
4ln + 3lnx = 7

Solving for variable 'l'.

Move all terms containing l to the left, all other terms to the right.

Reorder the terms:
-7 + 4ln + 3lnx = 7 + -7

Combine like terms: 7 + -7 = 0
-7 + 4ln + 3lnx = 0

The solution to this equation could not be determined.