ln(2y-5)-lny+3=0

Solution for ln(2y-5)-lny+3=0 equation:

Simplifying
ln(2y + -5) + -1lny + 3 = 0

Reorder the terms:
ln(-5 + 2y) + -1lny + 3 = 0
(-5 * ln + 2y * ln) + -1lny + 3 = 0
(-5ln + 2lny) + -1lny + 3 = 0

Reorder the terms:
3 + -5ln + 2lny + -1lny = 0

Combine like terms: 2lny + -1lny = 1lny
3 + -5ln + 1lny = 0

Solving
3 + -5ln + 1lny = 0

Solving for variable 'l'.

Move all terms containing l to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -5ln + -3 + 1lny = 0 + -3

Reorder the terms:
3 + -3 + -5ln + 1lny = 0 + -3

Combine like terms: 3 + -3 = 0
0 + -5ln + 1lny = 0 + -3
-5ln + 1lny = 0 + -3

Combine like terms: 0 + -3 = -3
-5ln + 1lny = -3

Reorder the terms:
3 + -5ln + 1lny = -3 + 3

Combine like terms: -3 + 3 = 0
3 + -5ln + 1lny = 0

The solution to this equation could not be determined.