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D( x )
(3/2)*x-5 <= 0
(3/2)*x-5 <= 0
(3/2)*x-5 <= 0
3/2*x-5 <= 0 // + 5
3/2*x <= 5 // : 3/2
x <= 5/3/2
x <= 10/3
x in (10/3:+oo)
ln((3/2)*x-5) = 0
ln((3/2)*x-5) = ln(e^0)
(3/2)*x-5 = e^0
(3/2)*x-e^0-5 = 0
3/2*x-6 = 0 // + 6
3/2*x = 6 // : 3/2
x = 6/3/2
x = 4
x = 4
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