ln(3/2x-5)=0

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Solution for ln(3/2x-5)=0 equation: 


D( x )

(3/2)*x-5 <= 0

(3/2)*x-5 <= 0

(3/2)*x-5 <= 0

3/2*x-5 <= 0 // + 5

3/2*x <= 5 // : 3/2

x <= 5/3/2

x <= 10/3

x in (10/3:+oo)

ln((3/2)*x-5) = 0

ln((3/2)*x-5) = ln(e^0)

(3/2)*x-5 = e^0

(3/2)*x-e^0-5 = 0

3/2*x-6 = 0 // + 6

3/2*x = 6 // : 3/2

x = 6/3/2

x = 4

x = 4

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