ln(3x+1)-ln(2x+1)=0

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Solution for ln(3x+1)-ln(2x+1)=0 equation:


Simplifying
ln(3x + 1) + -1ln(2x + 1) = 0

Reorder the terms:
ln(1 + 3x) + -1ln(2x + 1) = 0
(1 * ln + 3x * ln) + -1ln(2x + 1) = 0
(1ln + 3lnx) + -1ln(2x + 1) = 0

Reorder the terms:
1ln + 3lnx + -1ln(1 + 2x) = 0
1ln + 3lnx + (1 * -1ln + 2x * -1ln) = 0
1ln + 3lnx + (-1ln + -2lnx) = 0

Reorder the terms:
1ln + -1ln + 3lnx + -2lnx = 0

Combine like terms: 1ln + -1ln = 0
0 + 3lnx + -2lnx = 0
3lnx + -2lnx = 0

Combine like terms: 3lnx + -2lnx = 1lnx
1lnx = 0

Solving
1lnx = 0

Solving for variable 'l'.

Move all terms containing l to the left, all other terms to the right.

Divide each side by '1'.
lnx = 0

Simplifying
lnx = 0

The solution to this equation could not be determined.

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