ln(3x-1)-ln(2x-1)=1

Solution for ln(3x-1)-ln(2x-1)=1 equation:

Simplifying
ln(3x + -1) + -1ln(2x + -1) = 1

Reorder the terms:
ln(-1 + 3x) + -1ln(2x + -1) = 1
(-1 * ln + 3x * ln) + -1ln(2x + -1) = 1
(-1ln + 3lnx) + -1ln(2x + -1) = 1

Reorder the terms:
-1ln + 3lnx + -1ln(-1 + 2x) = 1
-1ln + 3lnx + (-1 * -1ln + 2x * -1ln) = 1
-1ln + 3lnx + (1ln + -2lnx) = 1

Reorder the terms:
-1ln + 1ln + 3lnx + -2lnx = 1

Combine like terms: -1ln + 1ln = 0
0 + 3lnx + -2lnx = 1
3lnx + -2lnx = 1

Combine like terms: 3lnx + -2lnx = 1lnx
1lnx = 1

Solving
1lnx = 1

Solving for variable 'l'.

Move all terms containing l to the left, all other terms to the right.

Divide each side by '1nx'.
l = n-1x-1

Simplifying
l = n-1x-1