ln(5x)=1/2

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Solution for ln(5x)=1/2 equation: 


D( x )

5*x <= 0

5*x <= 0

5*x <= 0

5*x+0 <= 0 // - 0

5*x <= 0 // : 5

x <= 0/5

x <= 0

x in (0:+oo)

ln(5*x) = 1/2 // - 1/2

ln(5*x)-(1/2) = 0

ln(5*x)-1/2 = 0

ln(5*x)-1/2 = 0 // + 1/2

ln(5*x) = 1/2

ln(5*x) = ln(e^(1/2))

5*x = e^(1/2)

5*x-e^(1/2) = 0 // + e^(1/2)

5*x = e^(1/2) // : 5

x = (e^(1/2))/5

x = (e^(1/2))/5

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