ln(abs(2+y))+ln(abs(2-y))=3

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Solution for ln(abs(2+y))+ln(abs(2-y))=3 equation:


Simplifying
ln(abs(2 + y)) + ln(abs(2 + -1y)) = 3
ln((2 * abs + y * abs)) + ln(abs(2 + -1y)) = 3
ln((2abs + absy)) + ln(abs(2 + -1y)) = 3
(2abs * ln + absy * ln) + ln(abs(2 + -1y)) = 3
(2ablns + ablnsy) + ln(abs(2 + -1y)) = 3
2ablns + ablnsy + ln((2 * abs + -1y * abs)) = 3
2ablns + ablnsy + ln((2abs + -1absy)) = 3
2ablns + ablnsy + (2abs * ln + -1absy * ln) = 3
2ablns + ablnsy + (2ablns + -1ablnsy) = 3

Reorder the terms:
2ablns + 2ablns + ablnsy + -1ablnsy = 3

Combine like terms: 2ablns + 2ablns = 4ablns
4ablns + ablnsy + -1ablnsy = 3

Combine like terms: ablnsy + -1ablnsy = 0
4ablns + 0 = 3
4ablns = 3

Solving
4ablns = 3

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Divide each side by '4blns'.
a = 0.75b-1l-1n-1s-1

Simplifying
a = 0.75b-1l-1n-1s-1

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