ln(t+1)=ln(3)+(t-4)

Solution for ln(t+1)=ln(3)+(t-4) equation:

Simplifying
ln(t + 1) = ln(3) + (t + -4)

Reorder the terms:
ln(1 + t) = ln(3) + (t + -4)
(1 * ln + t * ln) = ln(3) + (t + -4)
(1ln + lnt) = ln(3) + (t + -4)

Reorder the terms for easier multiplication:
1ln + lnt = 3ln + (t + -4)

Reorder the terms:
1ln + lnt = 3ln + (-4 + t)

Remove parenthesis around (-4 + t)
1ln + lnt = 3ln + -4 + t

Reorder the terms:
1ln + lnt = -4 + 3ln + t

Solving
1ln + lnt = -4 + 3ln + t

Solving for variable 'l'.

Move all terms containing l to the left, all other terms to the right.

Add '-3ln' to each side of the equation.
1ln + -3ln + lnt = -4 + 3ln + -3ln + t

Combine like terms: 1ln + -3ln = -2ln
-2ln + lnt = -4 + 3ln + -3ln + t

Combine like terms: 3ln + -3ln = 0
-2ln + lnt = -4 + 0 + t
-2ln + lnt = -4 + t

Reorder the terms:
4 + -2ln + lnt + -1t = -4 + t + 4 + -1t

Reorder the terms:
4 + -2ln + lnt + -1t = -4 + 4 + t + -1t

Combine like terms: -4 + 4 = 0
4 + -2ln + lnt + -1t = 0 + t + -1t
4 + -2ln + lnt + -1t = t + -1t

Combine like terms: t + -1t = 0
4 + -2ln + lnt + -1t = 0

The solution to this equation could not be determined.