ln(t+1)=ln(t-4)

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Solution for ln(t+1)=ln(t-4) equation:


Simplifying
ln(t + 1) = ln(t + -4)

Reorder the terms:
ln(1 + t) = ln(t + -4)
(1 * ln + t * ln) = ln(t + -4)
(1ln + lnt) = ln(t + -4)

Reorder the terms:
1ln + lnt = ln(-4 + t)
1ln + lnt = (-4 * ln + t * ln)
1ln + lnt = (-4ln + lnt)

Add '-1lnt' to each side of the equation.
1ln + lnt + -1lnt = -4ln + lnt + -1lnt

Combine like terms: lnt + -1lnt = 0
1ln + 0 = -4ln + lnt + -1lnt
1ln = -4ln + lnt + -1lnt

Combine like terms: lnt + -1lnt = 0
1ln = -4ln + 0
1ln = -4ln

Solving
1ln = -4ln

Solving for variable 'l'.

Move all terms containing l to the left, all other terms to the right.

Add '4ln' to each side of the equation.
1ln + 4ln = -4ln + 4ln

Combine like terms: 1ln + 4ln = 5ln
5ln = -4ln + 4ln

Combine like terms: -4ln + 4ln = 0
5ln = 0

Divide each side by '5'.
ln = 0

Simplifying
ln = 0

The solution to this equation could not be determined.

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