ln(x)+ln(4x)-ln(2x)=1

Solution for ln(x)+ln(4x)-ln(2x)=1 equation:

Simplifying
ln(x) + ln(4x) + -1ln(2x) = 1

Multiply ln * x
lnx + ln(4x) + -1ln(2x) = 1

Remove parenthesis around (4x)
lnx + ln * 4x + -1ln(2x) = 1

Reorder the terms for easier multiplication:
lnx + 4ln * x + -1ln(2x) = 1

Multiply ln * x
lnx + 4lnx + -1ln(2x) = 1

Remove parenthesis around (2x)
lnx + 4lnx + -1ln * 2x = 1

Reorder the terms for easier multiplication:
lnx + 4lnx + -1 * 2ln * x = 1

Multiply -1 * 2
lnx + 4lnx + -2ln * x = 1

Multiply ln * x
lnx + 4lnx + -2lnx = 1

Combine like terms: lnx + 4lnx = 5lnx
5lnx + -2lnx = 1

Combine like terms: 5lnx + -2lnx = 3lnx
3lnx = 1

Solving
3lnx = 1

Solving for variable 'l'.

Move all terms containing l to the left, all other terms to the right.

Divide each side by '3nx'.
l = 0.3333333333n-1x-1

Simplifying
l = 0.3333333333n-1x-1