ln(x+1)+ln(2x-1)=31

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Solution for ln(x+1)+ln(2x-1)=31 equation: 


Simplifying
ln(x + 1) + ln(2x + -1) = 31

Reorder the terms:
ln(1 + x) + ln(2x + -1) = 31
(1 * ln + x * ln) + ln(2x + -1) = 31
(1ln + lnx) + ln(2x + -1) = 31

Reorder the terms:
1ln + lnx + ln(-1 + 2x) = 31
1ln + lnx + (-1 * ln + 2x * ln) = 31
1ln + lnx + (-1ln + 2lnx) = 31

Reorder the terms:
1ln + -1ln + lnx + 2lnx = 31

Combine like terms: 1ln + -1ln = 0
0 + lnx + 2lnx = 31
lnx + 2lnx = 31

Combine like terms: lnx + 2lnx = 3lnx
3lnx = 31

Solving
3lnx = 31

Solving for variable 'l'.

Move all terms containing l to the left, all other terms to the right.

Divide each side by '3nx'.
l = 10.33333333n-1x-1

Simplifying
l = 10.33333333n-1x-1

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