ln(x+1)+ln(x-2)=1

Solution for ln(x+1)+ln(x-2)=1 equation:

Simplifying
ln(x + 1) + ln(x + -2) = 1

Reorder the terms:
ln(1 + x) + ln(x + -2) = 1
(1 * ln + x * ln) + ln(x + -2) = 1
(1ln + lnx) + ln(x + -2) = 1

Reorder the terms:
1ln + lnx + ln(-2 + x) = 1
1ln + lnx + (-2 * ln + x * ln) = 1
1ln + lnx + (-2ln + lnx) = 1

Reorder the terms:
1ln + -2ln + lnx + lnx = 1

Combine like terms: 1ln + -2ln = -1ln
-1ln + lnx + lnx = 1

Combine like terms: lnx + lnx = 2lnx
-1ln + 2lnx = 1

Solving
-1ln + 2lnx = 1

Solving for variable 'l'.

Move all terms containing l to the left, all other terms to the right.

Reorder the terms:
-1 + -1ln + 2lnx = 1 + -1

Combine like terms: 1 + -1 = 0
-1 + -1ln + 2lnx = 0

The solution to this equation could not be determined.