ln(x+1)-ln(x)=ln(1)

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Solution for ln(x+1)-ln(x)=ln(1) equation: 


Simplifying
ln(x + 1) + -1ln(x) = ln(1)

Reorder the terms:
ln(1 + x) + -1ln(x) = ln(1)
(1 * ln + x * ln) + -1ln(x) = ln(1)
(1ln + lnx) + -1ln(x) = ln(1)

Multiply ln * x
1ln + lnx + -1lnx = ln(1)

Combine like terms: lnx + -1lnx = 0
1ln + 0 = ln(1)
1ln = ln(1)

Reorder the terms for easier multiplication:
1ln = 1ln

Add '-1ln' to each side of the equation.
1ln + -1ln = 1ln + -1ln

Combine like terms: 1ln + -1ln = 0
0 = 1ln + -1ln

Combine like terms: 1ln + -1ln = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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