ln(x+1)-ln(x-1)=2

Solution for ln(x+1)-ln(x-1)=2 equation:

Simplifying
ln(x + 1) + -1ln(x + -1) = 2

Reorder the terms:
ln(1 + x) + -1ln(x + -1) = 2
(1 * ln + x * ln) + -1ln(x + -1) = 2
(1ln + lnx) + -1ln(x + -1) = 2

Reorder the terms:
1ln + lnx + -1ln(-1 + x) = 2
1ln + lnx + (-1 * -1ln + x * -1ln) = 2
1ln + lnx + (1ln + -1lnx) = 2

Reorder the terms:
1ln + 1ln + lnx + -1lnx = 2

Combine like terms: 1ln + 1ln = 2ln
2ln + lnx + -1lnx = 2

Combine like terms: lnx + -1lnx = 0
2ln + 0 = 2
2ln = 2

Solving
2ln = 2

Solving for variable 'l'.

Move all terms containing l to the left, all other terms to the right.

Divide each side by '2n'.
l = n-1

Simplifying
l = n-1