ln(x+1)-ln(x-2)=1

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Solution for ln(x+1)-ln(x-2)=1 equation: 


Simplifying
ln(x + 1) + -1ln(x + -2) = 1

Reorder the terms:
ln(1 + x) + -1ln(x + -2) = 1
(1 * ln + x * ln) + -1ln(x + -2) = 1
(1ln + lnx) + -1ln(x + -2) = 1

Reorder the terms:
1ln + lnx + -1ln(-2 + x) = 1
1ln + lnx + (-2 * -1ln + x * -1ln) = 1
1ln + lnx + (2ln + -1lnx) = 1

Reorder the terms:
1ln + 2ln + lnx + -1lnx = 1

Combine like terms: 1ln + 2ln = 3ln
3ln + lnx + -1lnx = 1

Combine like terms: lnx + -1lnx = 0
3ln + 0 = 1
3ln = 1

Solving
3ln = 1

Solving for variable 'l'.

Move all terms containing l to the left, all other terms to the right.

Divide each side by '3n'.
l = 0.3333333333n-1

Simplifying
l = 0.3333333333n-1

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