ln(x+1)-ln(x-2)=inx

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Solution for ln(x+1)-ln(x-2)=inx equation:


Simplifying
ln(x + 1) + -1ln(x + -2) = inx

Reorder the terms:
ln(1 + x) + -1ln(x + -2) = inx
(1 * ln + x * ln) + -1ln(x + -2) = inx
(1ln + lnx) + -1ln(x + -2) = inx

Reorder the terms:
1ln + lnx + -1ln(-2 + x) = inx
1ln + lnx + (-2 * -1ln + x * -1ln) = inx
1ln + lnx + (2ln + -1lnx) = inx

Reorder the terms:
1ln + 2ln + lnx + -1lnx = inx

Combine like terms: 1ln + 2ln = 3ln
3ln + lnx + -1lnx = inx

Combine like terms: lnx + -1lnx = 0
3ln + 0 = inx
3ln = inx

Solving
3ln = inx

Solving for variable 'l'.

Move all terms containing l to the left, all other terms to the right.

Divide each side by '3n'.
l = 0.3333333333ix

Simplifying
l = 0.3333333333ix

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