ln(x+2)+ln(x-1)=1

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Solution for ln(x+2)+ln(x-1)=1 equation:


Simplifying
ln(x + 2) + ln(x + -1) = 1

Reorder the terms:
ln(2 + x) + ln(x + -1) = 1
(2 * ln + x * ln) + ln(x + -1) = 1
(2ln + lnx) + ln(x + -1) = 1

Reorder the terms:
2ln + lnx + ln(-1 + x) = 1
2ln + lnx + (-1 * ln + x * ln) = 1
2ln + lnx + (-1ln + lnx) = 1

Reorder the terms:
2ln + -1ln + lnx + lnx = 1

Combine like terms: 2ln + -1ln = 1ln
1ln + lnx + lnx = 1

Combine like terms: lnx + lnx = 2lnx
1ln + 2lnx = 1

Solving
1ln + 2lnx = 1

Solving for variable 'l'.

Move all terms containing l to the left, all other terms to the right.

Reorder the terms:
-1 + 1ln + 2lnx = 1 + -1

Combine like terms: 1 + -1 = 0
-1 + 1ln + 2lnx = 0

The solution to this equation could not be determined.

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