ln(x+a)=ln(x)+ln(a)

Solution for ln(x+a)=ln(x)+ln(a) equation:

Simplifying
ln(x + a) = ln(x) + ln(a)

Reorder the terms:
ln(a + x) = ln(x) + ln(a)
(a * ln + x * ln) = ln(x) + ln(a)
(aln + lnx) = ln(x) + ln(a)

Multiply ln * x
aln + lnx = lnx + ln(a)

Multiply ln * a
aln + lnx = lnx + aln

Reorder the terms:
aln + lnx = aln + lnx

Add '-1aln' to each side of the equation.
aln + -1aln + lnx = aln + -1aln + lnx

Combine like terms: aln + -1aln = 0
0 + lnx = aln + -1aln + lnx
lnx = aln + -1aln + lnx

Combine like terms: aln + -1aln = 0
lnx = 0 + lnx
lnx = lnx

Add '-1lnx' to each side of the equation.
lnx + -1lnx = lnx + -1lnx

Combine like terms: lnx + -1lnx = 0
0 = lnx + -1lnx

Combine like terms: lnx + -1lnx = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.