ln(x-1)(x+2)=1

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Solution for ln(x-1)(x+2)=1 equation:


Simplifying
ln(x + -1)(x + 2) = 1

Reorder the terms:
ln(-1 + x)(x + 2) = 1

Reorder the terms:
ln(-1 + x)(2 + x) = 1

Multiply (-1 + x) * (2 + x)
ln(-1(2 + x) + x(2 + x)) = 1
ln((2 * -1 + x * -1) + x(2 + x)) = 1
ln((-2 + -1x) + x(2 + x)) = 1
ln(-2 + -1x + (2 * x + x * x)) = 1
ln(-2 + -1x + (2x + x2)) = 1

Combine like terms: -1x + 2x = 1x
ln(-2 + 1x + x2) = 1
(-2 * ln + 1x * ln + x2 * ln) = 1
(-2ln + 1lnx + lnx2) = 1

Solving
-2ln + 1lnx + lnx2 = 1

Solving for variable 'l'.

Move all terms containing l to the left, all other terms to the right.

Reorder the terms:
-1 + -2ln + 1lnx + lnx2 = 1 + -1

Combine like terms: 1 + -1 = 0
-1 + -2ln + 1lnx + lnx2 = 0

The solution to this equation could not be determined.

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