ln(x-1)+ln(x+1)-2ln(x)=0

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Solution for ln(x-1)+ln(x+1)-2ln(x)=0 equation: 


Simplifying
ln(x + -1) + ln(x + 1) + -2ln(x) = 0

Reorder the terms:
ln(-1 + x) + ln(x + 1) + -2ln(x) = 0
(-1 * ln + x * ln) + ln(x + 1) + -2ln(x) = 0
(-1ln + lnx) + ln(x + 1) + -2ln(x) = 0

Reorder the terms:
-1ln + lnx + ln(1 + x) + -2ln(x) = 0
-1ln + lnx + (1 * ln + x * ln) + -2ln(x) = 0
-1ln + lnx + (1ln + lnx) + -2ln(x) = 0

Multiply ln * x
-1ln + lnx + 1ln + lnx + -2lnx = 0

Reorder the terms:
-1ln + 1ln + lnx + lnx + -2lnx = 0

Combine like terms: -1ln + 1ln = 0
0 + lnx + lnx + -2lnx = 0
lnx + lnx + -2lnx = 0

Combine like terms: lnx + lnx = 2lnx
2lnx + -2lnx = 0

Combine like terms: 2lnx + -2lnx = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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