ln(x-1)-ln(x+1)=2

Solution for ln(x-1)-ln(x+1)=2 equation:

Simplifying
ln(x + -1) + -1ln(x + 1) = 2

Reorder the terms:
ln(-1 + x) + -1ln(x + 1) = 2
(-1 * ln + x * ln) + -1ln(x + 1) = 2
(-1ln + lnx) + -1ln(x + 1) = 2

Reorder the terms:
-1ln + lnx + -1ln(1 + x) = 2
-1ln + lnx + (1 * -1ln + x * -1ln) = 2
-1ln + lnx + (-1ln + -1lnx) = 2

Reorder the terms:
-1ln + -1ln + lnx + -1lnx = 2

Combine like terms: -1ln + -1ln = -2ln
-2ln + lnx + -1lnx = 2

Combine like terms: lnx + -1lnx = 0
-2ln + 0 = 2
-2ln = 2

Solving
-2ln = 2

Solving for variable 'l'.

Move all terms containing l to the left, all other terms to the right.

Divide each side by '-2n'.
l = -1n-1

Simplifying
l = -1n-1