ln(x-2)+ln(2x+1)=5

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Solution for ln(x-2)+ln(2x+1)=5 equation: 


Simplifying
ln(x + -2) + ln(2x + 1) = 5

Reorder the terms:
ln(-2 + x) + ln(2x + 1) = 5
(-2 * ln + x * ln) + ln(2x + 1) = 5
(-2ln + lnx) + ln(2x + 1) = 5

Reorder the terms:
-2ln + lnx + ln(1 + 2x) = 5
-2ln + lnx + (1 * ln + 2x * ln) = 5
-2ln + lnx + (1ln + 2lnx) = 5

Reorder the terms:
-2ln + 1ln + lnx + 2lnx = 5

Combine like terms: -2ln + 1ln = -1ln
-1ln + lnx + 2lnx = 5

Combine like terms: lnx + 2lnx = 3lnx
-1ln + 3lnx = 5

Solving
-1ln + 3lnx = 5

Solving for variable 'l'.

Move all terms containing l to the left, all other terms to the right.

Reorder the terms:
-5 + -1ln + 3lnx = 5 + -5

Combine like terms: 5 + -5 = 0
-5 + -1ln + 3lnx = 0

The solution to this equation could not be determined.

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