ln(x-4)+ln(4x+1)=5

Solution for ln(x-4)+ln(4x+1)=5 equation:

Simplifying
ln(x + -4) + ln(4x + 1) = 5

Reorder the terms:
ln(-4 + x) + ln(4x + 1) = 5
(-4 * ln + x * ln) + ln(4x + 1) = 5
(-4ln + lnx) + ln(4x + 1) = 5

Reorder the terms:
-4ln + lnx + ln(1 + 4x) = 5
-4ln + lnx + (1 * ln + 4x * ln) = 5
-4ln + lnx + (1ln + 4lnx) = 5

Reorder the terms:
-4ln + 1ln + lnx + 4lnx = 5

Combine like terms: -4ln + 1ln = -3ln
-3ln + lnx + 4lnx = 5

Combine like terms: lnx + 4lnx = 5lnx
-3ln + 5lnx = 5

Solving
-3ln + 5lnx = 5

Solving for variable 'l'.

Move all terms containing l to the left, all other terms to the right.

Reorder the terms:
-5 + -3ln + 5lnx = 5 + -5

Combine like terms: 5 + -5 = 0
-5 + -3ln + 5lnx = 0

The solution to this equation could not be determined.