ln(y)+(1/3)*ln(x)=c

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Solution for ln(y)+(1/3)*ln(x)=c equation: 


D( x )

x <= 0

x <= 0

x in (0:+oo)

ln(y)+(1/3)*ln(x) = c // - c

ln(y)+(1/3)*ln(x)-c = 0

t_2 = ln(x)

t_3 = ln(y)

ln(y)-c+(1/3)*t_2 = 0

t_2/3-c+t_3 = 0

(3*(-c))/3+t_2/3+(3*t_3)/3 = 0

3*(-c)+t_2+3*t_3 = 0

t_2-3*c+3*t_3 = 0

(t_2-3*c+3*t_3)/3 = 0

(t_2-3*c+3*t_3)/3 = 0 // * 3

t_2-3*c+3*t_3 = 0

t_2-3*c+3*t_3 = 0 // - 3*t_3-3*c

t_2 = -(3*t_3-3*c)

t_2 = -(3*ln(y)-3*c)

ln(x) = -(3*ln(y)-3*c)

ln(x) = ln(e^(-(3*ln(y)-3*c)))

x = e^(-(3*ln(y)-3*c))

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