ln(y+1)+ln(y-1)=1

Solution for ln(y+1)+ln(y-1)=1 equation:

Simplifying
ln(y + 1) + ln(y + -1) = 1

Reorder the terms:
ln(1 + y) + ln(y + -1) = 1
(1 * ln + y * ln) + ln(y + -1) = 1
(1ln + lny) + ln(y + -1) = 1

Reorder the terms:
1ln + lny + ln(-1 + y) = 1
1ln + lny + (-1 * ln + y * ln) = 1
1ln + lny + (-1ln + lny) = 1

Reorder the terms:
1ln + -1ln + lny + lny = 1

Combine like terms: 1ln + -1ln = 0
0 + lny + lny = 1
lny + lny = 1

Combine like terms: lny + lny = 2lny
2lny = 1

Solving
2lny = 1

Solving for variable 'l'.

Move all terms containing l to the left, all other terms to the right.

Divide each side by '2ny'.
l = 0.5n-1y-1

Simplifying
l = 0.5n-1y-1