ln(y+1)=4x+ln(c)

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Solution for ln(y+1)=4x+ln(c) equation:


Simplifying
ln(y + 1) = 4x + ln(c)

Reorder the terms:
ln(1 + y) = 4x + ln(c)
(1 * ln + y * ln) = 4x + ln(c)
(1ln + lny) = 4x + ln(c)

Multiply ln * c
1ln + lny = 4x + cln

Reorder the terms:
1ln + lny = cln + 4x

Solving
1ln + lny = cln + 4x

Solving for variable 'l'.

Move all terms containing l to the left, all other terms to the right.

Add '-1cln' to each side of the equation.
1ln + -1cln + lny = cln + -1cln + 4x

Reorder the terms:
-1cln + 1ln + lny = cln + -1cln + 4x

Combine like terms: cln + -1cln = 0
-1cln + 1ln + lny = 0 + 4x
-1cln + 1ln + lny = 4x

Combine like terms: 4x + -4x = 0
-1cln + 1ln + lny + -4x = 0

The solution to this equation could not be determined.

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