ln(y-1)+ln(x+1)=2

Solution for ln(y-1)+ln(x+1)=2 equation:

Simplifying
ln(y + -1) + ln(x + 1) = 2

Reorder the terms:
ln(-1 + y) + ln(x + 1) = 2
(-1 * ln + y * ln) + ln(x + 1) = 2
(-1ln + lny) + ln(x + 1) = 2

Reorder the terms:
-1ln + lny + ln(1 + x) = 2
-1ln + lny + (1 * ln + x * ln) = 2
-1ln + lny + (1ln + lnx) = 2

Reorder the terms:
-1ln + 1ln + lnx + lny = 2

Combine like terms: -1ln + 1ln = 0
0 + lnx + lny = 2
lnx + lny = 2

Solving
lnx + lny = 2

Solving for variable 'l'.

Move all terms containing l to the left, all other terms to the right.

Reorder the terms:
-2 + lnx + lny = 2 + -2

Combine like terms: 2 + -2 = 0
-2 + lnx + lny = 0

The solution to this equation could not be determined.