log(2b-2)=log(-b+10)

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Solution for log(2b-2)=log(-b+10) equation:


Simplifying
log(2b + -2) = log(-1b + 10)

Reorder the terms:
glo(-2 + 2b) = log(-1b + 10)
(-2 * glo + 2b * glo) = log(-1b + 10)

Reorder the terms:
(2bglo + -2glo) = log(-1b + 10)
(2bglo + -2glo) = log(-1b + 10)

Reorder the terms:
2bglo + -2glo = glo(10 + -1b)
2bglo + -2glo = (10 * glo + -1b * glo)

Reorder the terms:
2bglo + -2glo = (-1bglo + 10glo)
2bglo + -2glo = (-1bglo + 10glo)

Solving
2bglo + -2glo = -1bglo + 10glo

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add 'bglo' to each side of the equation.
2bglo + bglo + -2glo = -1bglo + bglo + 10glo

Combine like terms: 2bglo + bglo = 3bglo
3bglo + -2glo = -1bglo + bglo + 10glo

Combine like terms: -1bglo + bglo = 0
3bglo + -2glo = 0 + 10glo
3bglo + -2glo = 10glo

Add '2glo' to each side of the equation.
3bglo + -2glo + 2glo = 10glo + 2glo

Combine like terms: -2glo + 2glo = 0
3bglo + 0 = 10glo + 2glo
3bglo = 10glo + 2glo

Combine like terms: 10glo + 2glo = 12glo
3bglo = 12glo

Divide each side by '3glo'.
b = 4

Simplifying
b = 4

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