log(2x+1)+(x+4)=1

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Solution for log(2x+1)+(x+4)=1 equation:


Simplifying
log(2x + 1) + (x + 4) = 1

Reorder the terms:
glo(1 + 2x) + (x + 4) = 1
(1 * glo + 2x * glo) + (x + 4) = 1
(1glo + 2glox) + (x + 4) = 1

Reorder the terms:
1glo + 2glox + (4 + x) = 1

Remove parenthesis around (4 + x)
1glo + 2glox + 4 + x = 1

Reorder the terms:
4 + 1glo + 2glox + x = 1

Solving
4 + 1glo + 2glox + x = 1

Solving for variable 'g'.

Move all terms containing g to the left, all other terms to the right.

Add '-4' to each side of the equation.
4 + 1glo + 2glox + -4 + x = 1 + -4

Reorder the terms:
4 + -4 + 1glo + 2glox + x = 1 + -4

Combine like terms: 4 + -4 = 0
0 + 1glo + 2glox + x = 1 + -4
1glo + 2glox + x = 1 + -4

Combine like terms: 1 + -4 = -3
1glo + 2glox + x = -3

Add '-1x' to each side of the equation.
1glo + 2glox + x + -1x = -3 + -1x

Combine like terms: x + -1x = 0
1glo + 2glox + 0 = -3 + -1x
1glo + 2glox = -3 + -1x

Reorder the terms:
3 + 1glo + 2glox + x = -3 + -1x + 3 + x

Reorder the terms:
3 + 1glo + 2glox + x = -3 + 3 + -1x + x

Combine like terms: -3 + 3 = 0
3 + 1glo + 2glox + x = 0 + -1x + x
3 + 1glo + 2glox + x = -1x + x

Combine like terms: -1x + x = 0
3 + 1glo + 2glox + x = 0

The solution to this equation could not be determined.

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