log(2x+1)+log(5)=4

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Solution for log(2x+1)+log(5)=4 equation:


Simplifying
log(2x + 1) + log(5) = 4

Reorder the terms:
glo(1 + 2x) + log(5) = 4
(1 * glo + 2x * glo) + log(5) = 4
(1glo + 2glox) + log(5) = 4

Reorder the terms for easier multiplication:
1glo + 2glox + 5glo = 4

Reorder the terms:
1glo + 5glo + 2glox = 4

Combine like terms: 1glo + 5glo = 6glo
6glo + 2glox = 4

Solving
6glo + 2glox = 4

Solving for variable 'g'.

Move all terms containing g to the left, all other terms to the right.

Reorder the terms:
-4 + 6glo + 2glox = 4 + -4

Combine like terms: 4 + -4 = 0
-4 + 6glo + 2glox = 0

Factor out the Greatest Common Factor (GCF), '2'.
2(-2 + 3glo + glox) = 0

Ignore the factor 2.

Subproblem 1

Set the factor '(-2 + 3glo + glox)' equal to zero and attempt to solve: Simplifying -2 + 3glo + glox = 0 Solving -2 + 3glo + glox = 0 Move all terms containing g to the left, all other terms to the right. Add '2' to each side of the equation. -2 + 3glo + 2 + glox = 0 + 2 Reorder the terms: -2 + 2 + 3glo + glox = 0 + 2 Combine like terms: -2 + 2 = 0 0 + 3glo + glox = 0 + 2 3glo + glox = 0 + 2 Combine like terms: 0 + 2 = 2 3glo + glox = 2 The solution to this equation could not be determined. This subproblem is being ignored because a solution could not be determined. The solution to this equation could not be determined.

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