log(2x+1)-log(2x-2)=1

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Solution for log(2x+1)-log(2x-2)=1 equation: 


Simplifying
log(2x + 1) + -1log(2x + -2) = 1

Reorder the terms:
glo(1 + 2x) + -1log(2x + -2) = 1
(1 * glo + 2x * glo) + -1log(2x + -2) = 1
(1glo + 2glox) + -1log(2x + -2) = 1

Reorder the terms:
1glo + 2glox + -1glo(-2 + 2x) = 1
1glo + 2glox + (-2 * -1glo + 2x * -1glo) = 1
1glo + 2glox + (2glo + -2glox) = 1

Reorder the terms:
1glo + 2glo + 2glox + -2glox = 1

Combine like terms: 1glo + 2glo = 3glo
3glo + 2glox + -2glox = 1

Combine like terms: 2glox + -2glox = 0
3glo + 0 = 1
3glo = 1

Solving
3glo = 1

Solving for variable 'g'.

Move all terms containing g to the left, all other terms to the right.

Divide each side by '3lo'.
g = 0.3333333333l-1o-1

Simplifying
g = 0.3333333333l-1o-1

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