log(2x+1)-log(3x-2)=2

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Solution for log(2x+1)-log(3x-2)=2 equation:


Simplifying
log(2x + 1) + -1log(3x + -2) = 2

Reorder the terms:
glo(1 + 2x) + -1log(3x + -2) = 2
(1 * glo + 2x * glo) + -1log(3x + -2) = 2
(1glo + 2glox) + -1log(3x + -2) = 2

Reorder the terms:
1glo + 2glox + -1glo(-2 + 3x) = 2
1glo + 2glox + (-2 * -1glo + 3x * -1glo) = 2
1glo + 2glox + (2glo + -3glox) = 2

Reorder the terms:
1glo + 2glo + 2glox + -3glox = 2

Combine like terms: 1glo + 2glo = 3glo
3glo + 2glox + -3glox = 2

Combine like terms: 2glox + -3glox = -1glox
3glo + -1glox = 2

Solving
3glo + -1glox = 2

Solving for variable 'g'.

Move all terms containing g to the left, all other terms to the right.

Reorder the terms:
-2 + 3glo + -1glox = 2 + -2

Combine like terms: 2 + -2 = 0
-2 + 3glo + -1glox = 0

The solution to this equation could not be determined.

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