log(2x+1)=1+log(x-2)

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Solution for log(2x+1)=1+log(x-2) equation:


Simplifying
log(2x + 1) = 1 + log(x + -2)

Reorder the terms:
glo(1 + 2x) = 1 + log(x + -2)
(1 * glo + 2x * glo) = 1 + log(x + -2)
(1glo + 2glox) = 1 + log(x + -2)

Reorder the terms:
1glo + 2glox = 1 + glo(-2 + x)
1glo + 2glox = 1 + (-2 * glo + x * glo)
1glo + 2glox = 1 + (-2glo + glox)

Solving
1glo + 2glox = 1 + -2glo + glox

Solving for variable 'g'.

Move all terms containing g to the left, all other terms to the right.

Add '2glo' to each side of the equation.
1glo + 2glo + 2glox = 1 + -2glo + 2glo + glox

Combine like terms: 1glo + 2glo = 3glo
3glo + 2glox = 1 + -2glo + 2glo + glox

Combine like terms: -2glo + 2glo = 0
3glo + 2glox = 1 + 0 + glox
3glo + 2glox = 1 + glox

Add '-1glox' to each side of the equation.
3glo + 2glox + -1glox = 1 + glox + -1glox

Combine like terms: 2glox + -1glox = 1glox
3glo + 1glox = 1 + glox + -1glox

Combine like terms: glox + -1glox = 0
3glo + 1glox = 1 + 0
3glo + 1glox = 1

Reorder the terms:
-1 + 3glo + 1glox = 1 + -1

Combine like terms: 1 + -1 = 0
-1 + 3glo + 1glox = 0

The solution to this equation could not be determined.

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