log(2x+1)log(2x-1)=1

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Solution for log(2x+1)log(2x-1)=1 equation:


Simplifying
log(2x + 1) * log(2x + -1) = 1

Reorder the terms:
glo(1 + 2x) * log(2x + -1) = 1

Reorder the terms:
glo(1 + 2x) * glo(-1 + 2x) = 1

Reorder the terms for easier multiplication:
glo * glo(1 + 2x)(-1 + 2x) = 1

Multiply glo * glo
g2l2o2(1 + 2x)(-1 + 2x) = 1

Multiply (1 + 2x) * (-1 + 2x)
g2l2o2(1(-1 + 2x) + 2x * (-1 + 2x)) = 1
g2l2o2((-1 * 1 + 2x * 1) + 2x * (-1 + 2x)) = 1
g2l2o2((-1 + 2x) + 2x * (-1 + 2x)) = 1
g2l2o2(-1 + 2x + (-1 * 2x + 2x * 2x)) = 1
g2l2o2(-1 + 2x + (-2x + 4x2)) = 1

Combine like terms: 2x + -2x = 0
g2l2o2(-1 + 0 + 4x2) = 1
g2l2o2(-1 + 4x2) = 1
(-1 * g2l2o2 + 4x2 * g2l2o2) = 1
(-1g2l2o2 + 4g2l2o2x2) = 1

Solving
-1g2l2o2 + 4g2l2o2x2 = 1

Solving for variable 'g'.

Move all terms containing g to the left, all other terms to the right.

Reorder the terms:
-1 + -1g2l2o2 + 4g2l2o2x2 = 1 + -1

Combine like terms: 1 + -1 = 0
-1 + -1g2l2o2 + 4g2l2o2x2 = 0

The solution to this equation could not be determined.

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