log(2x+3)-log(3x-4)=2

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Solution for log(2x+3)-log(3x-4)=2 equation:


Simplifying
log(2x + 3) + -1log(3x + -4) = 2

Reorder the terms:
glo(3 + 2x) + -1log(3x + -4) = 2
(3 * glo + 2x * glo) + -1log(3x + -4) = 2
(3glo + 2glox) + -1log(3x + -4) = 2

Reorder the terms:
3glo + 2glox + -1glo(-4 + 3x) = 2
3glo + 2glox + (-4 * -1glo + 3x * -1glo) = 2
3glo + 2glox + (4glo + -3glox) = 2

Reorder the terms:
3glo + 4glo + 2glox + -3glox = 2

Combine like terms: 3glo + 4glo = 7glo
7glo + 2glox + -3glox = 2

Combine like terms: 2glox + -3glox = -1glox
7glo + -1glox = 2

Solving
7glo + -1glox = 2

Solving for variable 'g'.

Move all terms containing g to the left, all other terms to the right.

Reorder the terms:
-2 + 7glo + -1glox = 2 + -2

Combine like terms: 2 + -2 = 0
-2 + 7glo + -1glox = 0

The solution to this equation could not be determined.

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