log(2x-1)+log(x+4)=1

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Solution for log(2x-1)+log(x+4)=1 equation:


Simplifying
log(2x + -1) + log(x + 4) = 1

Reorder the terms:
glo(-1 + 2x) + log(x + 4) = 1
(-1 * glo + 2x * glo) + log(x + 4) = 1
(-1glo + 2glox) + log(x + 4) = 1

Reorder the terms:
-1glo + 2glox + glo(4 + x) = 1
-1glo + 2glox + (4 * glo + x * glo) = 1
-1glo + 2glox + (4glo + glox) = 1

Reorder the terms:
-1glo + 4glo + 2glox + glox = 1

Combine like terms: -1glo + 4glo = 3glo
3glo + 2glox + glox = 1

Combine like terms: 2glox + glox = 3glox
3glo + 3glox = 1

Solving
3glo + 3glox = 1

Solving for variable 'g'.

Move all terms containing g to the left, all other terms to the right.

Reorder the terms:
-1 + 3glo + 3glox = 1 + -1

Combine like terms: 1 + -1 = 0
-1 + 3glo + 3glox = 0

The solution to this equation could not be determined.

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