log(2x-1)-log(x-2)=2

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Solution for log(2x-1)-log(x-2)=2 equation:


Simplifying
log(2x + -1) + -1log(x + -2) = 2

Reorder the terms:
glo(-1 + 2x) + -1log(x + -2) = 2
(-1 * glo + 2x * glo) + -1log(x + -2) = 2
(-1glo + 2glox) + -1log(x + -2) = 2

Reorder the terms:
-1glo + 2glox + -1glo(-2 + x) = 2
-1glo + 2glox + (-2 * -1glo + x * -1glo) = 2
-1glo + 2glox + (2glo + -1glox) = 2

Reorder the terms:
-1glo + 2glo + 2glox + -1glox = 2

Combine like terms: -1glo + 2glo = 1glo
1glo + 2glox + -1glox = 2

Combine like terms: 2glox + -1glox = 1glox
1glo + 1glox = 2

Solving
1glo + 1glox = 2

Solving for variable 'g'.

Move all terms containing g to the left, all other terms to the right.

Reorder the terms:
-2 + 1glo + 1glox = 2 + -2

Combine like terms: 2 + -2 = 0
-2 + 1glo + 1glox = 0

The solution to this equation could not be determined.

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