log(2x-4)+log(2x+1)=2

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Solution for log(2x-4)+log(2x+1)=2 equation:


Simplifying
log(2x + -4) + log(2x + 1) = 2

Reorder the terms:
glo(-4 + 2x) + log(2x + 1) = 2
(-4 * glo + 2x * glo) + log(2x + 1) = 2
(-4glo + 2glox) + log(2x + 1) = 2

Reorder the terms:
-4glo + 2glox + glo(1 + 2x) = 2
-4glo + 2glox + (1 * glo + 2x * glo) = 2
-4glo + 2glox + (1glo + 2glox) = 2

Reorder the terms:
-4glo + 1glo + 2glox + 2glox = 2

Combine like terms: -4glo + 1glo = -3glo
-3glo + 2glox + 2glox = 2

Combine like terms: 2glox + 2glox = 4glox
-3glo + 4glox = 2

Solving
-3glo + 4glox = 2

Solving for variable 'g'.

Move all terms containing g to the left, all other terms to the right.

Reorder the terms:
-2 + -3glo + 4glox = 2 + -2

Combine like terms: 2 + -2 = 0
-2 + -3glo + 4glox = 0

The solution to this equation could not be determined.

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