log(3+b)=log(5c-2)

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Solution for log(3+b)=log(5c-2) equation: 


Simplifying
log(3 + b) = log(5c + -2)
(3 * glo + b * glo) = log(5c + -2)

Reorder the terms:
(bglo + 3glo) = log(5c + -2)
(bglo + 3glo) = log(5c + -2)

Reorder the terms:
bglo + 3glo = glo(-2 + 5c)
bglo + 3glo = (-2 * glo + 5c * glo)

Reorder the terms:
bglo + 3glo = (5cglo + -2glo)
bglo + 3glo = (5cglo + -2glo)

Solving
bglo + 3glo = 5cglo + -2glo

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-3glo' to each side of the equation.
bglo + 3glo + -3glo = 5cglo + -2glo + -3glo

Combine like terms: 3glo + -3glo = 0
bglo + 0 = 5cglo + -2glo + -3glo
bglo = 5cglo + -2glo + -3glo

Combine like terms: -2glo + -3glo = -5glo
bglo = 5cglo + -5glo

Divide each side by 'glo'.
b = 5c + -5

Simplifying
b = 5c + -5

Reorder the terms:
b = -5 + 5c

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