log(3x+1)-Log(x-1)=2

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Solution for log(3x+1)-Log(x-1)=2 equation: 


Simplifying
log(3x + 1) + -1Log(x + -1) = 2

Reorder the terms:
glo(1 + 3x) + -1Log(x + -1) = 2
(1 * glo + 3x * glo) + -1Log(x + -1) = 2
(1glo + 3glox) + -1Log(x + -1) = 2

Reorder the terms:
1glo + 3glox + -1goL(-1 + x) = 2
1glo + 3glox + (-1 * -1goL + x * -1goL) = 2
1glo + 3glox + (1goL + -1goxL) = 2

Solving
1glo + 3glox + 1goL + -1goxL = 2

Solving for variable 'g'.

Move all terms containing g to the left, all other terms to the right.

Reorder the terms:
-2 + 1glo + 3glox + 1goL + -1goxL = 2 + -2

Combine like terms: 2 + -2 = 0
-2 + 1glo + 3glox + 1goL + -1goxL = 0

The solution to this equation could not be determined.

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