log(3x+2)+log(4x-1)=121

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Solution for log(3x+2)+log(4x-1)=121 equation:


Simplifying
log(3x + 2) + log(4x + -1) = 121

Reorder the terms:
glo(2 + 3x) + log(4x + -1) = 121
(2 * glo + 3x * glo) + log(4x + -1) = 121
(2glo + 3glox) + log(4x + -1) = 121

Reorder the terms:
2glo + 3glox + glo(-1 + 4x) = 121
2glo + 3glox + (-1 * glo + 4x * glo) = 121
2glo + 3glox + (-1glo + 4glox) = 121

Reorder the terms:
2glo + -1glo + 3glox + 4glox = 121

Combine like terms: 2glo + -1glo = 1glo
1glo + 3glox + 4glox = 121

Combine like terms: 3glox + 4glox = 7glox
1glo + 7glox = 121

Solving
1glo + 7glox = 121

Solving for variable 'g'.

Move all terms containing g to the left, all other terms to the right.

Reorder the terms:
-121 + 1glo + 7glox = 121 + -121

Combine like terms: 121 + -121 = 0
-121 + 1glo + 7glox = 0

The solution to this equation could not be determined.

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